Operații cu numere raționale – [2]

25 bonus points

23 successes

English

Partea a doua a exercițiilor ce necesită operații în mulțimea numerelor raționale și mai ales a celor negative.

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Question 1 of 10

1. Question
1 points
${(\frac{1}{2})}^{0} + {(\frac{1}{2})}^{1} + {(\frac{1}{2})}^{2} + {(\frac{1}{2})}^{3} + {(\frac{1}{2})}^{4} + {(\frac{1}{2})}^{5} =$
- 1
- $\frac{63}{32}$
- $\frac{63}{16}$
- ${(\frac{1}{2})}^{15}$
Correct

Incorrect
Question 2 of 10

2. Question
1 points
$1 \frac{2}{3} : (- \frac{5}{6}) =$
- + 2
- $- \frac{2}{13}$
- $- \frac{1}{2}$
- - 2
Correct

Incorrect
Question 3 of 10

3. Question
1 points
${(- \frac{1}{2})}^{5} =$
- $- \frac{1}{32}$
- $+ \frac{1}{16}$
- $- \frac{5}{32}$
- -1
Correct

Incorrect
Question 4 of 10

4. Question
1 points
$3 - 1 \frac{1}{3} : \frac{1}{3} - (- \frac{1}{3} - \frac{2}{3}) =$
- $3$
- $\frac{4}{3}$
- $0$
- $\frac{1}{3}$
Correct

Incorrect
Question 5 of 10

5. Question
1 points
${[{(- \frac{2}{5})}^{6}]}^{13} =$
- ${(- \frac{2}{5})}^{78}$
- $- \frac{2}{78}$
- ${(- \frac{2}{5})}^{87}$
- ${(- \frac{3}{5})}^{68}$
Correct

Incorrect
Question 6 of 10

6. Question
1 points
${(- \frac{2}{3})}^{4} \cdot {(- \frac{2}{3})}^{16} \cdot {(\frac{2}{3})}^{7} =$
- $\frac{2}{3}$
- ${(- \frac{2}{3})}^{27}$
- ${(- \frac{2}{3})}^{21}$
- ${(\frac{2}{3})}^{27}$
Correct

Incorrect
Question 7 of 10

7. Question
1 points
${(- 13 + 1234 - 76^{8} + 12^{234})}^{0} =$
- 1
- 0
- -13
- 1234
Correct

Incorrect
Question 8 of 10

8. Question
1 points
$- \frac{1}{4} \cdot \frac{12}{13} =$
- -3
- -1
- $- \frac{3}{13}$
- $\frac{3}{13}$
Correct

Incorrect
Question 9 of 10

9. Question
1 points
$1 - \frac{1}{2} \cdot \frac{1}{3} =$
- $\frac{5}{6}$
- $- \frac{5}{6}$
- $\frac{6}{5}$
- $\frac{1}{2}$
Correct

Incorrect
Question 10 of 10

10. Question
1 points
$\frac{3}{4} : (- \frac{9}{16}) + (- \frac{1}{5}) : (+ \frac{11}{15}) =$
- $- \frac{53}{33}$
- $- \frac{54}{33}$
- $\frac{11}{33}$
- $- \frac{52}{33}$
Correct

Incorrect

Examples of questions from "Operații cu numere raționale – [2]"

$1 \frac{2}{3} : (- \frac{5}{6}) =$
$1 - \frac{1}{2} \cdot \frac{1}{3} =$
${(- \frac{2}{3})}^{4} \cdot {(- \frac{2}{3})}^{16} \cdot {(\frac{2}{3})}^{7} =$